A) 14

 Let the son's present age be x years .Then, (38 - x) = x => x= 19.

 Son's age 5 years back = (19 - 5) = 14 years

C) 15

 Let the present ages of son and father be x and (60 -x) years respectively.

 Then, (60 - x) - 5= 4(x - 5)

 55 - x = 4x - 20

 5x = 75 => x = 15

A) 24

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

Then, 5x+3/4x+3 = 11/9

9(5x + 3) = 11(4x + 3)

45x + 27 = 44x + 33

45x - 44x = 33 - 27

x = 6.

Anand's present age = 4x = 24 years.

D) 9

Let the mother's present age be x years.

Then, the person's present age = 1/5 x years. (1/5) x = 7 = (1/3)(x+7)

⇒ 3x + 105 = 5x + 35

⇒ x = 35

c) 6:13

The ratio of Seema's age to the age of her mother is 5:12.

The difference of their ages 12x - 5x = 21, ⇒ x= 3

∴ Ratio of their ages after 3 years = 5x+3: 12x+3

⇒ 5*3+3:12*3+3

⇒ 18:39 ⇒ 6:13

B) 13:6

Let father's age be 3x and son's age be x years

=>3X*X=147

=>X^2=49 => 7

Father's age after 5 years = 3x + 5 = 26 years

D) 10

Let Rajeev's present age be x years.

Rajeev's age after 15 years = (x + 15) years.

Rajeev's age 5 years back = (x - 5) years

Then ATQ,

x + 15 = 5 (x - 5)

x + 15 = 5x - 25

=> x = 10

Hence, Rajeev's present age = x = 10 years.

D) data inadequate

Then Sivagami’s age = A + 2

After 6 years the total of their ages will be 7 times of what?

Not clear.

So the given data are inadequate.

C) 22

Let the son's present age be x years. Then, man's present age = (x + 24) years

=> (x + 24) + 2 = 2(x + 2)

=> x + 26 = 2x + 4

So, x = 22

C) 15

Krish’s age = 3A and Vaibhav’s age = 5A

(3A+9)/(5A+9) = 3/4

4 (3A + 9) = 3 (5A + 9)

A = 3

Therefore, Vaibhav’s age = 15 years.

A) 12 years, 44 years

  Present ages of son and father be x years (56 -x)years

 (56- x +4) = 3(x + 4) or 4x =48 or x = 12

 Ages are 12 years, 44 years

A) 18 years

  Let the present age of the person be x years.

 Then, 3(x + 3) - 3(x - 3) = x

 3x + 9 - 3x + 9 = x => x = 18

A) 12

(A + B) - (B + C) = 12

A - C = 12

D) 10 years

Let C's age be x years

Then, B's age = 2x years

A's age = (2x + 2) years

(2x + 2) + 2x + x = 27

5x = 25 => x = 5

Hence, B's age = 2x = 10 years

A) 4

Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12.

We know that the sum of their ages is 50

so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50

=> x= 4

The youngest child is 4 years old.

D) 56 years

6 years ago average age of A,B,C,D = 30 years

∴ 6 years ago total age of A, B, C, D = 30 x 4 = 120 years

∴ Total present age of A, B, C, D = 120 + 6 x 4 = 144 years

If E's present age is x years, (144 + x) / 5 = 40

Therefore, X= 56.

A) 2 yrs

29 x 2 = 58

20 x 3 = 60

2 years

Therefore, the age of child is 2 years.

C) 10 years

Then Sivagami’s age = A + 2

After 6 years the total of their ages will be 7 times of what?

Not clear.

So the given data are inadequate.

B) 27 years

Let the son's age be x years and the father's age be 3x years.

⇒ (3x-6) = 7(x-6)

⇒ 3x-6 = 7x-42

⇒ x = 9

∴ Present age of the father =3x= 3*9= 27 years

C) 15

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

20x = 80

x = 4.

Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

C) 27 yrs

  5/6 x p = p - 5

 p = 30

 His wifes age = 30 - 3 = 27 yrs.

A) 25 years

  Let varun's age = x yrs.

 From the given conditions,
x+1 = 2(x-12)

 x = 25 years.

C) 24.5 years

Let Rahul's age be x years.

Then, Sachin's age = (x - 7) years.

X-7 : X = 7:9

9x - 63 = 7x

2x = 63 x = 31.5

Hence, Sachin's age =(x - 7) = 24.5 years.

C) 68

when my age is 24, my mothers age is double of my age

=> 48 yrs is my mothers age

=> Difference is 48 - 24 = 24 years.

When my age is 44

=> My mother is 44 + 24 = 68 years aged.

A) 4 years

Let Ishika and her daughter present ages be p and q

p = 4/3(p - 9)

=> p = 36 years

Hence, Ishika's present age = 36 years and Her daughter's present age = 1/6 x 36 = 6 years

Now, required her daughter’s age three years ago = 6 - 3 = 3 years.

A) 36 years

Let Roshan's age be x years.

Then, Dinesh 's age = (x - 9) years.

(x - 9)/x = 4/5

x = 45 Hence, Dinesh's age = (x - 9) = 36 years.

C) 20 years

Let us assume x years ago

At present Shivani is 60 years old and Ritu is 80 years old.

X years ago : Shivani’s age = (60-x) and Ritu’s age (80-x)

Ratio of their ages x years ago was 4:6

(60-x) / (80-x) = 4/6

6 (60-x) = 4 (80-x)

360-6x = 320-4x

6x – 4x = 360 – 320

2x = 40 =>x = 20

Therefore, 20 years ago their age ratio was 4:6

A) 20 years

Here, we have to calculate: How many years ago the ratio of their ages was 3:2. Let us assume x years ago

x years ago: Saransh’s age = (50 – x) and Nazma's age = (40 – x)

Given, the ratio of their ages was 3:2

(50-x) / (40-x) = 3/2

Solving, we get: x = 20

Therefore, the answer is 20 years.

C) 8.7 years

Let John’s present age be x

John’s age before 5 years = (x - 5)

John’s age after 10 years = (x + 10)

We are given that, John’s age after 10 years (x + 10) is 5 times his age 5 years back (x –5)

Therefore, (x + 10) = 5 (x – 5)

Solving the equation, we get

x + 10 = 5x – 25

4x = 35 x = 8.75 years

A) 12 years

James father present age = x

James age = 2/7 x

James brother age = 2x/7 + 3

x = 42

=> 2x/7 = 12 yrs